Hooke’s Law
Determine the Spring Constant
Hooke`s Law states that the restoring force of a spring is directly proportional to a small displacement. In equation form, we write
F = -kx       
where x is the size of the displacement. The proportionality constant k is specific for each spring.
The object of this virtual lab is to determine the spring constant k.
Displacement is measured in centimeters. Each of the blue weights has a mass of 50 grams. The gray virtual weight hanger has no mass.
Snapshots of the lab are found in the four figures that follow.





50 grams mass is 2 cm displacement.

100 grams mass is 4 cm displacement.


150 grams mass is 6 cm displacement.

200 grams mass is 8 cm displacement.

Mass  (grams) 
Displacement (cm)

 50
2

100
4

150
6

200
8


These data have been entered into the table to the left.
For each snapshot above the downward pull of gravity is balanced by the upward pull of the spring. A force or free-body diagram of this is shown on the right-hand side.
Note that the restoring spring force is given by Hooke`s Law as kx.



This equilibrium can be expressed as
W = kx.       
W is the weight of the added mass. Therefore, the spring constant k is the slope of the straight line W versus x plot.
Weight is mass times the acceleration of gravity or W = mg where g is about 980 cm/sec2. Using this relationship weights are computed for the masses in the table above. The results are on the right.
Data from this table are plotted on the graph below. Note that the points fall precisely on the line since this is a virtual experiment.
Weight  (dynes) 
Displacement (cm)

 49000
2

98000
4

147000
6

196000
8



Standard non-virtual lab data will be scattered a bit. Just spot the best straight line fit and draw the line in with a ruler (or run a linear least squares calculation).


As stated above the relationship depicted on the graph is W = kx where k is the spring constant. Therefore, the spring constant is the slope of the line.